using default values on function Passing arguments by reference and return values

<?php
function alert($type=5) {

if ($type==1){

return "num is equal to 1  ";

}


else  {


return  " Bigger than 1";


}
}

echo alert(1);


?>

Passing arguments by reference ¶

To have an argument to a function always passed by reference, prepend an ampersand (&) to the argument name in the function definition:

<?php
function alert(&$type=5) {


$type +=6;
if ($type==1){


return "type is equal to 1  ";

}


else  {


return  " $type Bigger than 1";


}
}

echo alert();